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Author SHA1 Message Date
f971917640 Solve 2025 day 9 pt 1
Pt 2 is almost there. Need a better flood fill
algorithm.
2025-12-09 14:49:19 +01:00
267ecaebc1 better visualzier 2025-12-09 14:48:57 +01:00
2 changed files with 114 additions and 4 deletions

View file

@ -1,4 +1,5 @@
import re import re
from math import inf
# Directions/Adjacents for 2D matrices, in the order UP, RIGHT, DOWN, LEFT # Directions/Adjacents for 2D matrices, in the order UP, RIGHT, DOWN, LEFT
D = [ D = [
@ -78,12 +79,26 @@ def mdbg(m):
print("".join(r)) print("".join(r))
def vdbg(seen, h, w, C="#", M=None): def vdbg(seen, mask=("#", "."), M=None):
"""Print-debug visited positions of a matrix""" """Print-debug visited positions of a matrix"""
t = inf
l = inf
b = 0
r = 0
for y, x in seen:
t = min(t, y)
r = max(r, x)
b = max(b, y)
l = min(l, x)
H = b - t + 1
W = r - l + 1
osr = t
osc = l
C, Z = mask
def _m(r, c): def _m(r, c):
return M[r][c] if M else "." return M[r][c] if M else Z
for r in range(h): for r in range(H):
print("".join([C if (r, c) in seen else _m(r, c) for c in range(w)])) print("".join([C if (r + osr, c + osc) in seen else _m(r, c) for c in range(W)]))
def vvdbg(seen, h, w): def vvdbg(seen, h, w):

View file

@ -0,0 +1,95 @@
from itertools import combinations
from output import ints
def solve(data):
p1 = 0
p2 = 0
A = [tuple(ints(pos)) for pos in data.splitlines()]
S = A[0]
V = set()
B = set()
while True:
V.add(S)
y, x = S
he = [(r, c) for r, c in A if r == y and (r, c) not in V]
ve = [(r, c) for r, c in A if c == x and (r, c) not in V]
if not he and not ve:
E = A[0]
elif he and ve:
E = min(min(he), min(ve))
elif he and not ve:
E = min(he)
else:
E = min(ve)
y2, x2 = E
for r in range(min(y, y2), max(y, y2) + 1):
for c in range(min(x, x2), max(x, x2) + 1):
B.add((r, c))
if E == A[0]:
break
S = E
# find out a better start for Flood fill by visualizing
Y = 1841
X = 53478
# or, find a way to floodfill without BFS
# end
y, x = Y, X
Q = [(y, x)]
V = V | B
while Q:
yx = Q.pop()
if yx in V:
continue
V.add(yx)
y, x = yx
for dy, dx in D:
Q.append((dy + y, dx + x))
for a, b in combinations(A, r=2):
y1, x1 = a
y2, x2 = b
x = abs(x1 - x2) + 1
y = abs(y1 - y2) + 1
p1 = max(p1, x * y)
if (
len(
set(
[
(min(y1, y2), min(x1, x2)),
(min(y1, y2), max(x1, x2)),
(max(y1, y2), min(x1, x2)),
(max(y1, y2), max(x1, x2)),
]
)
- V
)
== 0
):
p2 = max(p2, max(p2, x * y))
return p1, p2
if __name__ == "__main__":
inp = """
7,1
11,1
11,7
9,7
9,5
2,5
2,3
7,3 """.strip()
with open("./input/09.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 4749838800
assert p2 == 1624057680