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Author SHA1 Message Date
c24d74892a Solve 2022 day 5 pt 1-2
Important not to strip trailing whitespace from this one :)
2025-11-23 18:56:38 +01:00
4c538f7683 Solve 2022 day 4 pt 1-2 2025-11-23 18:56:38 +01:00
62d19f09f6 Solve 2022 day 3 pt 1-2 2025-11-23 18:56:38 +01:00
8e49f8b3d5 Solve 2022 day 2 pt 1-2 2025-11-23 18:56:38 +01:00
6a207b2721 Solve 2022 day 1 pt 1-2 2025-11-23 18:56:38 +01:00
ac604e67bc Inititate AOC 2022 in python 2025-11-23 18:56:38 +01:00
8 changed files with 528 additions and 0 deletions

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# Advent of Code 2022
Solutions for #aoc2022 in Python 3 (3.13.4).
Programming setup:
- Lenovo Thinkpad T14
- OpenSUSE Tumbleweed with labwc
- Helix editor
- Vivaldi
- Foot
## Help scripts
Display all solved puzzles:
python aoc.py
To bootstrap a new puzzle (creates `input/<day_no>.txt` and `output/day_<day_no>.py`):
python aoc.py <day_no> new
Manually copy the puzzle input from https://adventofcode.com and paste it in `input/<day_no>.txt`
to start coding.
wl-paste > input/<day_no>.txt
Solve separate puzzle (replace `XX` with the puzzle number):
python -m output.day_XX
Solve separate puzzle using stdin (replace `XX` with the puzzle number):
wl-paste | python -m output.day_XX
cat tmpfile | python -m output.day_XX
Execute separate puzzle on file save (replace `XX` with the puzzle number):
ls output/*.py | entr -c -s 'wlpaste | python -m output.day_XX'
ls output/*.py | entr -c -s 'cat tmpfile | python -m output.day_XX'
ls output/*.py | entr -c -r python -m output.day_XX
(requires `entr` and `wl-paste`, Mac users can instead use `pbpaste`. If you
prefer X at Linux, use `xclip -selection clipboard -o`).
To lint files:
ls output/*.py | entr -r -c flake8 output --ignore=E741,E501,E203

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import sys
from pathlib import Path
def headline(n):
"""Print day number and name, followed by a ruler. Used by the answer decorator"""
print(f"\nDay {int(n)} - https://adventofcode.com/{year}/day/{int(n)}\n")
year = 2022
try:
_, day_no, *name = sys.argv
except ValueError:
day_no = None
name = None
Path("./input").mkdir(parents=True, exist_ok=True)
Path("./output").mkdir(parents=True, exist_ok=True)
if day_no and name:
name = " ".join(name)
padded_no = day_no.zfill(2)
with open("output/day_{}.py".format(padded_no), "w") as s:
s.write(
f"""
import re
from collections import deque, Counter, defaultdict
from heapq import heappop, heappush
from itertools import compress, combinations, chain, permutations
from output import matrix, D, DD, ADJ, ints, mhd, mdbg, vdbg, cw, ccw, bk
def solve(data):
p1 = None
p2 = None
return p1, p2
if __name__ == "__main__":
import os
# use dummy data
inp = \"\"\"
replace me
\"\"\".strip()
# uncomment to instead use stdin
# import sys; inp = sys.stdin.read().strip()
# uncomment to use AoC provided puzzle input
# with open("./input/{padded_no}.txt", "r") as f:
# inp = f.read().strip()
# uncomment to do initial data processing shared by part 1-2
p1, p2 = solve(inp)
print(p1)
os.system(f"echo {{p1}} | wl-copy")
# print(p2)
# os.system(f"echo {{p2}} | wl-copy")
# uncomment and replace 0 with actual output to refactor code
# and ensure nonbreaking changes
# assert p1 == 0
# assert p2 == 0
""".strip()
+ "\n"
)
exit(0)
print(
f"\n\033[95m\033[1mAdvent of Code {year}\033[0m"
"\n###################"
"\n\n\033[96mby Anders Englöf Ytterström\033[0m"
)
stars = 0
for i in [str(n).zfill(2) for n in range(1, 26)]:
if not day_no or day_no.zfill(2) == i:
try:
day = __import__(
"output.day_{}".format(i),
globals(),
locals(),
["solve"],
0,
)
with open(f"./input/{i}.txt", "r") as f:
data = f.read().strip()
headline(i)
try:
data = day.presolve(data)
except AttributeError:
pass
try:
p1, p2 = day.solve(data)
except AttributeError:
pass
if p1:
print(f" \033[92m1)\033[0m {p1}")
stars += 1
if p2:
print(f" \033[92m2)\033[0m {p2}")
stars += 1
except IOError:
pass
except ImportError:
pass
if not day_no:
print(f"\nStars: {stars}")
print("".join("*" if n < stars else "" for n in range(50)))
print("")

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import re
# Directions/Adjacents for 2D matrices, in the order UP, RIGHT, DOWN, LEFT
D = [
(-1, 0),
(0, 1),
(1, 0),
(0, -1),
]
Di = [
(-1, -1),
(-1, 1),
(1, -1),
(1, 1),
]
# Directions for 2D matrices, as a dict with keys U, R, D, L
DD = {
"U": (-1, 0),
"R": (0, 1),
"D": (1, 0),
"L": (0, -1),
}
DDa = {
"^": (-1, 0),
">": (0, 1),
"v": (1, 0),
"<": (0, -1),
}
# Adjacent relative positions including diagonals for 2D matrices, in the order NW, N, NE, W, E, SW, S, SE
ADJ = [
(-1, -1),
(-1, 0),
(1, -1),
(0, -1),
(0, 1),
(1, 1),
(1, 0),
(1, -1),
]
def ints(s):
"""Extract all integers from a string"""
return [int(n) for n in re.findall(r"\d+", s)]
def sints(s):
"""Extract all signed integers from a string"""
return [int(n) for n in re.findall(r"-?\d+", s)]
def mhd(a, b):
"""Calculates the Manhattan distance between 2 positions in the format (y, x) or (x, y)"""
ar, ac = a
br, bc = b
return abs(ar - br) + abs(ac - bc)
def matrix(d):
"""Transform a string into an iterable matrix. Returns the matrix, row count and col count"""
m = [tuple(r) for r in d.split()]
return m, len(m), len(m[0])
def mdbg(m):
"""Print-debug a matrix"""
for r in m:
print("".join(r))
def vdbg(seen, h, w):
"""Print-debug visited positions of a matrix"""
for r in range(h):
print("".join(["#" if (r, c) in seen else " " for c in range(w)]))
def cw(y, x):
"""Flip a (y, x) direction counterwise: U->R, R->D, D->L, L->U.
>>> cw(-1, 0)
(0, 1)
>>> cw(0, 1)
(1, 0)
>>> cw(1, 0)
(0, -1)
>>> cw(0, -1)
(-1, 0)
"""
return (x, y) if y == 0 else (x, -y)
def ccw(y, x):
"""Flip a (y, x) direction counterwise: U->L, L->D, D->R, R->U.
>>> ccw(-1, 0)
(0, -1)
>>> ccw(0, -1)
(1, 0)
>>> ccw(1, 0)
(0, 1)
>>> ccw(0, 1)
(-1, 0)
"""
return (x, y) if x == 0 else (-x, y)
def bfs(S, E=None):
"""BFS algorithm, equal weighted nodes"""
seen = set()
q = [(S, 0)]
g = {} # graph, required to be provided at some point
while q:
m, w = q.pop(0)
if m in seen:
continue
seen.add(m)
# investigate here
for s in g[m]:
q.append((s, w + 1))
# return insights
def mhd_search(r, c, R=20):
"""returns all coords that are within R manhattan distance from (r,c)"""
p = set()
for d in range(1, R + 1):
p.add((r, c + d))
p.add((r, c - d))
p.add((r + d, c))
p.add((r - d, c))
for dd in range(d):
p.add((r - dd, c - d + dd))
p.add((r + dd, c - d + dd))
p.add((r - dd, c - dd + d))
p.add((r + dd, c - dd + d))
return p
def dijkstras(grid, start, target):
"""
1. Create an array that holds the distance of each vertex from the starting
vertex. Initially, set this distance to infinity for all vertices except
the starting vertex which should be set to 0.
2. Create a priority queue (heap) and insert the starting vertex with its
distance of 0.
3. While there are still vertices left in the priority queue, select the vertex
with the smallest recorded distance from the starting vertex and visit its
neighboring vertices.
4. For each neighboring vertex, check if it is visited already or not. If it
isnt visited yet, calculate its tentative distance by adding its weight
to the smallest distance found so far for its parent/previous node
(starting vertex in case of first-level vertices).
5. If this tentative distance is smaller than previously recorded value
(if any), update it in our distances array.
6. Finally, add this visited vertex with its updated distance to our priority
queue and repeat step-3 until we have reached our destination or exhausted
all nodes.
"""
import heapq
target = max(grid)
seen = set()
queue = [(start, 0)]
while queue:
cost, pos, direction, steps = heapq.heappop(queue)
y, x = pos
dy, dx = direction
if pos == target:
return cost
if ((pos, "and stuff")) in seen:
continue
seen.add((pos, "and stuff"))
neighbors = []
for n in neighbors:
heapq.heappush(queue, ("stuffs"))
return -1
def bk(graph, p, r=set(), x=set()):
"""Bron-Kerbosch algoritm, no pivot: https://en.wikipedia.org/wiki/Bron%E2%80%93Kerbosch_algorithm"""
if not p and not x:
yield r
while p:
v = p.pop()
yield from bk(graph, p & set(graph[v]), r | {v}, x & graph[v])
x.add(v)

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from output import ints
def solve(data):
E = data.split("\n\n")
p1 = 0
C = []
for e in E:
e = sum(ints(e))
p1 = max(p1, e)
C.append(e)
p2 = sum(sorted(C, reverse=True)[:3])
return p1, p2
if __name__ == "__main__":
with open("./input/01.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 66616
assert p2 == 199172

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def solve(data):
S1 = {
"A X": 1 + 3,
"A Y": 2 + 6,
"A Z": 3 + 0,
"B X": 1 + 0,
"B Y": 2 + 3,
"B Z": 3 + 6,
"C X": 1 + 6,
"C Y": 2 + 0,
"C Z": 3 + 3,
}
S2 = {
"A X": 3 + 0,
"A Y": 1 + 3,
"A Z": 2 + 6,
"B X": 1 + 0,
"B Y": 2 + 3,
"B Z": 3 + 6,
"C X": 2 + 0,
"C Y": 3 + 3,
"C Z": 1 + 6,
}
R = data.splitlines()
p1 = sum(S1[r] for r in R)
p2 = sum(S2[r] for r in R)
return p1, p2
if __name__ == "__main__":
with open("./input/02.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 12772
assert p2 == 11618

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def solve(data):
rs = data.split()
p1 = sum(map(_p1, rs))
p2 = sum(map(_p2, zip(rs[::3], rs[1::3], rs[2::3])))
return p1, p2
def _p1(rs):
c = (set(rs[: len(rs) // 2]) & set(rs[len(rs) // 2 :])).pop()
return ord(c) - 96 if c.islower() else ord(c) - 38
def _p2(rsg):
c = (set(rsg[0]) & set(rsg[1]) & set(rsg[2])).pop()
return ord(c) - 96 if c.islower() else ord(c) - 38
if __name__ == "__main__":
with open("./input/03.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 7817
assert p2 == 2444

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from output import ints
def solve(data):
p1 = sum(_p1(line) for line in data.split())
p2 = sum(_p2(line) for line in data.split())
return p1, p2
def _p1(data):
a1, a2, b1, b2 = ints(data)
return (a1 >= b1 and a2 <= b2) or (b1 >= a1 and b2 <= a2)
def _p2(data):
a1, a2, b1, b2 = ints(data)
return len(set(range(a1, a2 + 1)) & set(range(b1, b2 + 1))) > 0
if __name__ == "__main__":
with open("./input/04.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 507
assert p2 == 897

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from copy import deepcopy
from collections import defaultdict
from output import ints
def solve(data):
state, program = data.split("\n\n")
labels, *state = state.splitlines()[::-1]
num = max(ints(labels))
stacks = defaultdict(list)
for r, text in enumerate(state):
for c in range(4 * num):
if c % 4 == 1:
if text[c] != " ":
stacks[c // 4 + 1].append(text[c])
p1 = _act(program, deepcopy(stacks))
p2 = _act(program, deepcopy(stacks), r=9001)
return p1, p2
def _act(program, stacks, r=9000):
for line in program.splitlines():
count, old, new = ints(line)
match r:
case 9000:
for _ in range(count):
stacks[new].append(stacks[old].pop())
case 9001:
stacks[new] += stacks[old][-count:]
stacks[old] = stacks[old][:-count]
return "".join(s[-1] for s in stacks.values())
if __name__ == "__main__":
with open("./input/05.txt", "r") as f:
inp = f.read()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == "ZRLJGSCTR"
assert p2 == "PRTTGRFPB"