Solve 2025 day 9 pt 1

Pt 2 is almost there. Need a better flood fill
algorithm.
This commit is contained in:
Anders Englöf Ytterström 2025-12-09 14:49:19 +01:00 committed by Anders Englöf Ytterström
parent 34fb92403e
commit ae676bf112

View file

@ -0,0 +1,95 @@
from itertools import combinations
from output import ints
def solve(data):
p1 = 0
p2 = 0
A = [tuple(ints(pos)) for pos in data.splitlines()]
S = A[0]
V = set()
B = set()
while True:
V.add(S)
y, x = S
he = [(r, c) for r, c in A if r == y and (r, c) not in V]
ve = [(r, c) for r, c in A if c == x and (r, c) not in V]
if not he and not ve:
E = A[0]
elif he and ve:
E = min(min(he), min(ve))
elif he and not ve:
E = min(he)
else:
E = min(ve)
y2, x2 = E
for r in range(min(y, y2), max(y, y2) + 1):
for c in range(min(x, x2), max(x, x2) + 1):
B.add((r, c))
if E == A[0]:
break
S = E
# find out a better start for Flood fill by visualizing
Y = 1841
X = 53478
# or, find a way to floodfill without BFS
# end
y, x = Y, X
Q = [(y, x)]
V = V | B
while Q:
yx = Q.pop()
if yx in V:
continue
V.add(yx)
y, x = yx
for dy, dx in D:
Q.append((dy + y, dx + x))
for a, b in combinations(A, r=2):
y1, x1 = a
y2, x2 = b
x = abs(x1 - x2) + 1
y = abs(y1 - y2) + 1
p1 = max(p1, x * y)
if (
len(
set(
[
(min(y1, y2), min(x1, x2)),
(min(y1, y2), max(x1, x2)),
(max(y1, y2), min(x1, x2)),
(max(y1, y2), max(x1, x2)),
]
)
- V
)
== 0
):
p2 = max(p2, max(p2, x * y))
return p1, p2
if __name__ == "__main__":
inp = """
7,1
11,1
11,7
9,7
9,5
2,5
2,3
7,3 """.strip()
with open("./input/09.txt", "r") as f:
inp = f.read().strip()
p1, p2 = solve(inp)
print(p1)
print(p2)
assert p1 == 4749838800
assert p2 == 1624057680