Inititate AOC 2022 in python
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48
2022-python/README.md
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48
2022-python/README.md
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# Advent of Code 2022
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Solutions for #aoc2022 in Python 3 (3.13.4).
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Programming setup:
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- Lenovo Thinkpad T14
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- OpenSUSE Tumbleweed with labwc
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- Helix editor
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- Vivaldi
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- Foot
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## Help scripts
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Display all solved puzzles:
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python aoc.py
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To bootstrap a new puzzle (creates `input/<day_no>.txt` and `output/day_<day_no>.py`):
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python aoc.py <day_no> new
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Manually copy the puzzle input from https://adventofcode.com and paste it in `input/<day_no>.txt`
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to start coding.
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wl-paste > input/<day_no>.txt
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Solve separate puzzle (replace `XX` with the puzzle number):
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python -m output.day_XX
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Solve separate puzzle using stdin (replace `XX` with the puzzle number):
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wl-paste | python -m output.day_XX
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cat tmpfile | python -m output.day_XX
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Execute separate puzzle on file save (replace `XX` with the puzzle number):
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ls output/*.py | entr -c -s 'wlpaste | python -m output.day_XX'
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ls output/*.py | entr -c -s 'cat tmpfile | python -m output.day_XX'
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ls output/*.py | entr -c -r python -m output.day_XX
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(requires `entr` and `wl-paste`, Mac users can instead use `pbpaste`. If you
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prefer X at Linux, use `xclip -selection clipboard -o`).
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To lint files:
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ls output/*.py | entr -r -c flake8 output --ignore=E741,E501,E203
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115
2022-python/aoc.py
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115
2022-python/aoc.py
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import sys
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from pathlib import Path
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def headline(n):
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"""Print day number and name, followed by a ruler. Used by the answer decorator"""
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print(f"\nDay {int(n)} - https://adventofcode.com/{year}/day/{int(n)}\n")
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year = 2022
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try:
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_, day_no, *name = sys.argv
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except ValueError:
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day_no = None
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name = None
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Path("./input").mkdir(parents=True, exist_ok=True)
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Path("./output").mkdir(parents=True, exist_ok=True)
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if day_no and name:
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name = " ".join(name)
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padded_no = day_no.zfill(2)
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with open("output/day_{}.py".format(padded_no), "w") as s:
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s.write(
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f"""
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import re
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from collections import deque, Counter, defaultdict
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from heapq import heappop, heappush
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from itertools import compress, combinations, chain, permutations
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from output import matrix, D, DD, ADJ, ints, mhd, mdbg, vdbg, cw, ccw, bk
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def solve(data):
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p1 = None
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p2 = None
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return p1, p2
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if __name__ == "__main__":
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import os
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# use dummy data
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inp = \"\"\"
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replace me
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\"\"\".strip()
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# uncomment to instead use stdin
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# import sys; inp = sys.stdin.read().strip()
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# uncomment to use AoC provided puzzle input
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# with open("./input/{padded_no}.txt", "r") as f:
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# inp = f.read().strip()
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# uncomment to do initial data processing shared by part 1-2
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p1, p2 = solve(inp)
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print(p1)
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os.system(f"echo {{p1}} | wl-copy")
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# print(p2)
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# os.system(f"echo {{p2}} | wl-copy")
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# uncomment and replace 0 with actual output to refactor code
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# and ensure nonbreaking changes
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# assert p1 == 0
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# assert p2 == 0
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""".strip()
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+ "\n"
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)
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exit(0)
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print(
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f"\n\033[95m\033[1mAdvent of Code {year}\033[0m"
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"\n###################"
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"\n\n\033[96mby Anders Englöf Ytterström\033[0m"
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)
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stars = 0
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for i in [str(n).zfill(2) for n in range(1, 26)]:
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if not day_no or day_no.zfill(2) == i:
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try:
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day = __import__(
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"output.day_{}".format(i),
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globals(),
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locals(),
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["solve"],
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0,
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)
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with open(f"./input/{i}.txt", "r") as f:
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data = f.read().strip()
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headline(i)
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try:
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data = day.presolve(data)
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except AttributeError:
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pass
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try:
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p1, p2 = day.solve(data)
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except AttributeError:
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pass
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if p1:
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print(f" \033[92m1)\033[0m {p1}")
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stars += 1
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if p2:
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print(f" \033[92m2)\033[0m {p2}")
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stars += 1
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except IOError:
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pass
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except ImportError:
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pass
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if not day_no:
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print(f"\nStars: {stars}")
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print("".join("*" if n < stars else "•" for n in range(50)))
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print("")
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195
2022-python/output/__init__.py
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2022-python/output/__init__.py
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import re
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# Directions/Adjacents for 2D matrices, in the order UP, RIGHT, DOWN, LEFT
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D = [
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(-1, 0),
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(0, 1),
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(1, 0),
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(0, -1),
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]
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Di = [
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(-1, -1),
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(-1, 1),
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(1, -1),
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(1, 1),
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]
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# Directions for 2D matrices, as a dict with keys U, R, D, L
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DD = {
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"U": (-1, 0),
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"R": (0, 1),
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"D": (1, 0),
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"L": (0, -1),
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}
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DDa = {
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"^": (-1, 0),
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">": (0, 1),
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"v": (1, 0),
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"<": (0, -1),
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}
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# Adjacent relative positions including diagonals for 2D matrices, in the order NW, N, NE, W, E, SW, S, SE
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ADJ = [
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(-1, -1),
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(-1, 0),
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(1, -1),
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(0, -1),
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(0, 1),
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(1, 1),
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(1, 0),
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(1, -1),
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]
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def ints(s):
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"""Extract all integers from a string"""
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return [int(n) for n in re.findall(r"\d+", s)]
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def sints(s):
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"""Extract all signed integers from a string"""
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return [int(n) for n in re.findall(r"-?\d+", s)]
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def mhd(a, b):
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"""Calculates the Manhattan distance between 2 positions in the format (y, x) or (x, y)"""
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ar, ac = a
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br, bc = b
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return abs(ar - br) + abs(ac - bc)
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def matrix(d):
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"""Transform a string into an iterable matrix. Returns the matrix, row count and col count"""
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m = [tuple(r) for r in d.split()]
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return m, len(m), len(m[0])
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def mdbg(m):
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"""Print-debug a matrix"""
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for r in m:
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print("".join(r))
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def vdbg(seen, h, w):
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"""Print-debug visited positions of a matrix"""
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for r in range(h):
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print("".join(["#" if (r, c) in seen else " " for c in range(w)]))
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def cw(y, x):
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"""Flip a (y, x) direction counterwise: U->R, R->D, D->L, L->U.
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>>> cw(-1, 0)
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(0, 1)
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>>> cw(0, 1)
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(1, 0)
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>>> cw(1, 0)
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(0, -1)
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>>> cw(0, -1)
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(-1, 0)
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"""
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return (x, y) if y == 0 else (x, -y)
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def ccw(y, x):
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"""Flip a (y, x) direction counterwise: U->L, L->D, D->R, R->U.
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>>> ccw(-1, 0)
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(0, -1)
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>>> ccw(0, -1)
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(1, 0)
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>>> ccw(1, 0)
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(0, 1)
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>>> ccw(0, 1)
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(-1, 0)
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"""
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return (x, y) if x == 0 else (-x, y)
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def bfs(S, E=None):
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"""BFS algorithm, equal weighted nodes"""
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seen = set()
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q = [(S, 0)]
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g = {} # graph, required to be provided at some point
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while q:
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m, w = q.pop(0)
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if m in seen:
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continue
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seen.add(m)
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# investigate here
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for s in g[m]:
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q.append((s, w + 1))
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# return insights
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def mhd_search(r, c, R=20):
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"""returns all coords that are within R manhattan distance from (r,c)"""
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p = set()
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for d in range(1, R + 1):
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p.add((r, c + d))
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p.add((r, c - d))
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p.add((r + d, c))
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p.add((r - d, c))
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for dd in range(d):
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p.add((r - dd, c - d + dd))
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p.add((r + dd, c - d + dd))
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p.add((r - dd, c - dd + d))
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p.add((r + dd, c - dd + d))
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return p
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def dijkstras(grid, start, target):
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"""
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1. Create an array that holds the distance of each vertex from the starting
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vertex. Initially, set this distance to infinity for all vertices except
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the starting vertex which should be set to 0.
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2. Create a priority queue (heap) and insert the starting vertex with its
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distance of 0.
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3. While there are still vertices left in the priority queue, select the vertex
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with the smallest recorded distance from the starting vertex and visit its
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neighboring vertices.
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4. For each neighboring vertex, check if it is visited already or not. If it
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isn’t visited yet, calculate its tentative distance by adding its weight
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to the smallest distance found so far for its parent/previous node
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(starting vertex in case of first-level vertices).
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5. If this tentative distance is smaller than previously recorded value
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(if any), update it in our ‘distances’ array.
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6. Finally, add this visited vertex with its updated distance to our priority
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queue and repeat step-3 until we have reached our destination or exhausted
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all nodes.
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"""
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import heapq
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target = max(grid)
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seen = set()
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queue = [(start, 0)]
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while queue:
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cost, pos, direction, steps = heapq.heappop(queue)
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y, x = pos
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dy, dx = direction
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if pos == target:
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return cost
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if ((pos, "and stuff")) in seen:
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continue
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seen.add((pos, "and stuff"))
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neighbors = []
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for n in neighbors:
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heapq.heappush(queue, ("stuffs"))
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return -1
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def bk(graph, p, r=set(), x=set()):
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"""Bron-Kerbosch algoritm, no pivot: https://en.wikipedia.org/wiki/Bron%E2%80%93Kerbosch_algorithm"""
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if not p and not x:
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yield r
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while p:
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v = p.pop()
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yield from bk(graph, p & set(graph[v]), r | {v}, x & graph[v])
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x.add(v)
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Add table
Reference in a new issue