Solve 2024:12 p2 "Garden Groups"
Funny that original 2023 day 5 also was a PITA to figure out. Pt 1 was solved using BFS to flood-fill. After trying some different methods for pt 2, including: - wallcrawling, - side couting, - corner counting I never produced code to get past the test cases. - Wall crawling are hard due to overlapping regions. - corner couting and side counting are both hard, but will act as equally good solutions (since side count equals corner count). - Concave corners are hard, convex corners are easy. The final code is based on the posts on the solutions megathread. Changes: - Keep all areas in a set, defining a region. - find all convex and concave corners in each region. A new helper got introduced: Di, storing all diagonal neighbors for grid traversing. Convex corners: .. R. .R .. R. .. .. .R Concave corners: RR .R R. RR .R RR RR R.
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2 changed files with 53 additions and 61 deletions
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@ -9,6 +9,13 @@ D = [
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(0, -1),
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(0, -1),
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]
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]
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Di = [
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(-1, -1),
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(-1, 1),
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(1, -1),
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(1, 1),
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]
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# Directions for 2D matrices, as a dict with keys U, R, D, L
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# Directions for 2D matrices, as a dict with keys U, R, D, L
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DD = {
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DD = {
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"U": (-1, 0),
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"U": (-1, 0),
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@ -1,20 +1,19 @@
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import re
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from collections import deque
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from collections import Counter, defaultdict, deque
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from heapq import heappop, heappush
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from itertools import chain, combinations, compress, permutations
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from output import ADJ, DD, D, ccw, cw, ints, matrix, mdbg, mhd, vdbg
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from output import D, Di, cw, matrix
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def solve(data):
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def solve(data):
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grid, H, W = matrix(data)
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grid, H, W = matrix(data)
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p1 = 0
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fence_cost = 0
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fence_cost_w_discount = 0
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seen = set()
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seen = set()
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for r, row in enumerate(grid):
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for r in range(H):
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for c, col in enumerate(row):
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for c in range(W):
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if (r, c) in seen:
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if (r, c) in seen:
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continue
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continue
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areas = 0
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id = grid[r][c]
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regions = set()
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perimeters = 0
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perimeters = 0
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q = deque([(r, c)])
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q = deque([(r, c)])
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while q:
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while q:
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@ -22,67 +21,53 @@ def solve(data):
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if rc in seen:
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if rc in seen:
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continue
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continue
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seen.add(rc)
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seen.add(rc)
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areas += 1
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regions.add(rc)
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y, x = rc
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y, x = rc
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for dy, dx in D:
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for delta_y, delta_x in D:
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if (0 <= y + dy < H and 0 <= x + dx < W) and grid[y + dy][
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yn, xn = y + delta_y, x + delta_x
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x + dx
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if (0 <= yn < H and 0 <= xn < W) and grid[yn][xn] == id:
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] == col:
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q.append((yn, xn))
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q.append((y + dy, x + dx))
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else:
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else:
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perimeters += 1
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perimeters += 1
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p1 += areas * perimeters
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if len(regions) <= 2:
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p2 = None
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corners = 4
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return p1, p2
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else:
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corners = count_corners(regions)
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fence_cost += len(regions) * perimeters
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fence_cost_w_discount += len(regions) * corners
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return fence_cost, fence_cost_w_discount
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def count_corners(region):
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corners = 0
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for y, x in region:
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for delta_y, delta_x in D:
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# convex corners: one horisontal and one vertical
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# neighbor are not members of region
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delta_ycw, delta_xcw = cw(delta_y, delta_x)
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if (y + delta_y, x + delta_x) not in region and (
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y + delta_ycw,
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x + delta_xcw,
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) not in region:
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corners += 1
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for delta_y, delta_x in Di:
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# concave corners: the diagonal neighbor are not
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# member of region, but the connected horisontal
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# and vertical neighbors are
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if (
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(y + delta_y, x + delta_x) not in region
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and (y + delta_y, x) in region
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and (y, x + delta_x) in region
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):
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corners += 1
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return corners
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if __name__ == "__main__":
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if __name__ == "__main__":
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import os
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# use dummy data
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inp = """
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RRRRIICCFF
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RRRRIICCCF
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VVRRRCCFFF
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VVRCCCJFFF
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VVVVCJJCFE
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VVIVCCJJEE
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VVIIICJJEE
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MIIIIIJJEE
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MIIISIJEEE
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MMMISSJEEE
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""".strip()
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"""
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A region of R plants with price 12 * 18 = 216.
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A region of I plants with price 4 * 8 = 32.
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A region of C plants with price 14 * 28 = 392.
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A region of F plants with price 10 * 18 = 180.
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A region of V plants with price 13 * 20 = 260.
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A region of J plants with price 11 * 20 = 220.
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A region of C plants with price 1 * 4 = 4.
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A region of E plants with price 13 * 18 = 234.
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A region of I plants with price 14 * 22 = 308.
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A region of M plants with price 5 * 12 = 60.
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A region of S plants with price 3 * 8 = 24.
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"""
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# uncomment to instead use stdin
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# import sys; inp = sys.stdin.read().strip()
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# uncomment to use AoC provided puzzle input
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with open("./input/12.txt", "r") as f:
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with open("./input/12.txt", "r") as f:
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inp = f.read().strip()
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inp = f.read().strip()
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# uncomment to do initial data processing shared by part 1-2
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p1, p2 = solve(inp)
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p1, p2 = solve(inp)
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print(p1)
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print(p1)
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os.system(f"echo {p1} | wl-copy")
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print(p2)
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# print(p2)
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# os.system(f"echo {p2} | wl-copy")
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# uncomment and replace 0 with actual output to refactor code
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# and ensure nonbreaking changes
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assert p1 == 1446042
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# assert p2 == 0
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