Solve 2023:17 p1-2 "Clumsy Crucible"

Revenge, blast from the past etc!

Had to learn Dijkstra's for this one. Was as stuck
as one can be on AOC. This stopped my progress
2023, and kept me busy at least 20-30h this year
(2024) as well. I never came past part 1, but got
part 2 in minutes when I hit home.

Turns out the initial queue was to blame, after
studying Dijkstras, reading hints on the subreddit
and tutorials in blogs. I was off-by-1 in costs,
since I misplaced a read from the grid.

I also struggled a really, really long time with
a bug where I resetted the steps to aggresively.

What helped me to figure it out was to create
simpler test case grids and step-debug them.

Example 1:

241
321

should give a least heat loss of 6 in pt1.

Example 2:

11199
12199
99199
99131
99111

should give a least heat loss of 9 in pt2.
This commit is contained in:
Anders Englöf Ytterström 2024-12-02 00:10:19 +01:00
parent fb468c2199
commit 178d96494a
2 changed files with 156 additions and 0 deletions

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@ -80,3 +80,59 @@ def vdbg(seen, h, w):
"""Print-debug visited positions of a matrix""" """Print-debug visited positions of a matrix"""
for r in range(h): for r in range(h):
print("".join(["#" if (r, c) in seen else "." for c in range(w)])) print("".join(["#" if (r, c) in seen else "." for c in range(w)]))
"""
1. Create an array that holds the distance of each vertex from the starting
vertex. Initially, set this distance to infinity for all vertices except
the starting vertex which should be set to 0.
2. Create a priority queue (heap) and insert the starting vertex with its
distance of 0.
3. While there are still vertices left in the priority queue, select the vertex
with the smallest recorded distance from the starting vertex and visit its
neighboring vertices.
4. For each neighboring vertex, check if it is visited already or not. If it
isnt visited yet, calculate its tentative distance by adding its weight
to the smallest distance found so far for its parent/previous node
(starting vertex in case of first-level vertices).
5. If this tentative distance is smaller than previously recorded value
(if any), update it in our distances array.
6. Finally, add this visited vertex with its updated distance to our priority
queue and repeat step-3 until we have reached our destination or exhausted
all nodes.
"""
# https://pieriantraining.com/understanding-dijkstras-algorithm-in-python/
def dijkstra_algorithm(graph, start_node):
def min_distance(distances, visited):
min_val = float("inf")
min_index = -1
for i in range(len(distances)):
if distances[i] < min_val and i not in visited:
min_val = distances[i]
min_index = i
return min_index
num_nodes = len(graph)
distances = [float("inf")] * num_nodes
visited = []
distances[start_node] = 0
for i in range(num_nodes):
current_node = min_distance(distances, visited)
visited.append(current_node)
for j in range(num_nodes):
if graph[current_node][j] != 0:
new_distance = distances[current_node] + graph[current_node][j]
if new_distance < distances[j]:
distances[j] = new_distance
return distances

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@ -0,0 +1,100 @@
from heapq import heappop, heappush
from output import answer # D, DD, ADJ, ints, mhd, mdbg, vdbg
n = 17
title = "Clumsy Crucible"
@answer(1, "Using std crucible, least heat loss incured: {}")
def part_1(presolved):
return presolved[0]
@answer(2, "Using ultra crucible, least heat loss incured: {}")
def part_2(presolved):
return presolved[1]
def solve(data):
grid = {
(r, c): int(col)
for r, row in enumerate(data.split())
for c, col in enumerate(row)
}
p1 = least_heat_loss(grid, 1, 3)
p2 = least_heat_loss(grid, 4, 10)
return p1, p2
def least_heat_loss(grid, minsteps, maxsteps):
target = max(grid)
seen = set()
queue = [(0, (0, 0), (0, 1), 0)]
while queue:
cost, pos, direction, steps = heappop(queue)
y, x = pos
dy, dx = direction
if pos == target:
return cost
if ((pos, direction, steps)) in seen:
continue
seen.add((pos, direction, steps))
if steps >= minsteps:
cwdy, cwdx = clockwise(*direction)
if (cw := (y + cwdy, x + cwdx)) in grid:
cwy, cwx = cw
heappush(queue, (cost + grid[cw], (cwy, cwx), (cwdy, cwdx), 1))
ccwdy, ccwdx = counterclockwise(*direction)
if (ccw := (y + ccwdy, x + ccwdx)) in grid:
ccwy, ccwx = ccw
heappush(queue, (cost + grid[ccw], (ccwy, ccwx), (ccwdy, ccwdx), 1))
if steps < maxsteps and (fwd := (y + dy, x + dx)) in grid:
fwdy, fwdx = fwd
heappush(queue, (cost + grid[fwd], (fwdy, fwdx), direction, steps + 1))
return -1
def clockwise(y, x):
"""
>>> clockwise(-1, 0)
(0, 1)
>>> clockwise(0, 1)
(1, 0)
>>> clockwise(1, 0)
(0, -1)
>>> clockwise(0, -1)
(-1, 0)
"""
return (x, y) if y == 0 else (x, -y)
def counterclockwise(y, x):
"""
>>> counterclockwise(-1, 0)
(0, -1)
>>> counterclockwise(0, -1)
(1, 0)
>>> counterclockwise(1, 0)
(0, 1)
>>> counterclockwise(0, 1)
(-1, 0)
"""
return (x, y) if x == 0 else (-x, y)
if __name__ == "__main__":
with open("./input/17.txt", "r") as f:
inp = f.read().strip()
inp = solve(inp)
a = part_1(inp)
b = part_2(inp)